09 Apr '21 19:04>
@venda saidYep, you've got it. Just another way to skin the same cat!
O.k Joe ,I've got a bit further
Your formula C(11,2)*C(9,2)*C(7,2)*5! = 55*36*21*5! Is actually the same calculation as 11!/2!2!2!.
I just need to look at the probability part now!
As an aside,I looked in an book I once compiled when I encountered this sort of thing years ago and I had written::-
The way to find any number of objects "p" of one kind and "q" of another with ...[text shortened]... that in a spreadsheet but couldn't get the same answer.
I suppose I may have written it down wrong.