1. R
    Standard memberRemoved
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    03 May '21 23:432 edits
    A person drives from A to B to get to work at a constant speed of 30 km/hr. They were running a little late for a hot date, so they decided to rush a little bit on the way home. If the average speed the person traveled over the round trip form A to B and B to A was 55 km/hr, how fast were they traveling on the way home?
  2. Joined
    28 Feb '16
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    04 May '21 00:13
    @joe-shmo
    80kph
  3. RSA
    Joined
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    04 May '21 00:16
    @liljo said
    @joe-shmo
    80kph
    You can't add the speeds and divide by 2 to get 55 because the amount of time taken is different for each.
  4. Subscribervenda
    Dave
    S.Yorks.England
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    04 May '21 08:44
    @ashiitaka said
    You can't add the speeds and divide by 2 to get 55 because the amount of time taken is different for each.
    Correct because 55 is an average itself.
    I think the equations are 30+x/2 =55
    30x/55= y," y " being the answer.
    I'll try it later.
  5. Joined
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    04 May '21 09:47
    165 km/h?
  6. R
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    04 May '21 12:58
    Still Open
  7. Subscribervenda
    Dave
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    04 May '21 14:40
    @joe-shmo said
    Still Open
    Ok. I got the formula slightly wrong, but I have amended it and arrived at an answer.
    I can only hope there were no police about when he was driving home!!
    Reveal Hidden Content
    330 kph
  8. R
    Standard memberRemoved
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    04 May '21 14:52
    @venda

    Correct!
  9. R
    Standard memberRemoved
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    04 May '21 23:11
    @venda

    Feel free to write up the solution if you'd like.
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