8 queens on the board

8 queens on the board

Posers and Puzzles

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N

Joined
30 Mar 06
Moves
2481
02 Apr 06

On one chess board, place 8 pawns on the board... pretending they are all queens ....place them in such a position where no one queen can capture the other...another words there must be one on each row, one on each file and cant be placed on the same diagonal...start timing yourself

C

Earth Prime

Joined
16 Mar 05
Moves
35265
02 Apr 06

After you complete that, you must choose one of two doors to escape from. Only one is safe. There are also two idols in the room that you can ask one question to one of them, but one always lies, and one always tells the truth.

๐Ÿ˜ด

c

Joined
29 Apr 05
Moves
827
03 Apr 06

You know you chose the wrong door if you find sonhouse on the other side with a new astronomy puzzle for you.

๐Ÿ˜‰

a

THORNINYOURSIDE

Joined
04 Sep 04
Moves
245624
04 Apr 06

Originally posted by Narragansett
On one chess board, place 8 pawns on the board... pretending they are all queens ....place them in such a position where no one queen can capture the other...another words there must be one on each row, one on each file and cant be placed on the same diagonal...start timing yourself
I timed myself it took 16.3458761298736753462355 seconds. Unfortunately that is as accurate as my watch gets so I may have been slightly slower or slightly faster.

Z

Joined
20 Oct 05
Moves
611
04 Apr 06

Originally posted by adramforall
I timed myself it took 16.3458761298736753462355 seconds. Unfortunately that is as accurate as my watch gets so I may have been slightly slower or slightly faster.
I would say that's pretty damn accurate.

X
Cancerous Bus Crash

p^2.sin(phi)

Joined
06 Sep 04
Moves
25076
04 Apr 06

Originally posted by Zelinda
I would say that's pretty damn accurate.
I would say you are pretty damn stupid.

J

back in business

Joined
25 Aug 04
Moves
1264
04 Apr 06

Originally posted by XanthosNZ
I would say you are pretty damn stupid.
I would say nothing

X
Cancerous Bus Crash

p^2.sin(phi)

Joined
06 Sep 04
Moves
25076
04 Apr 06

Originally posted by Jusuh
I would say nothing
You say it best, when you say nothing at all.

r

Sabah, Malaysia

Joined
02 Mar 06
Moves
2541
11 Apr 06

Originally posted by Narragansett
On one chess board, place 8 pawns on the board... pretending they are all queens ....place them in such a position where no one queen can capture the other...another words there must be one on each row, one on each file and cant be placed on the same diagonal...start timing yourself
one problem....

it is impossible to do that

X
Cancerous Bus Crash

p^2.sin(phi)

Joined
06 Sep 04
Moves
25076
11 Apr 06

Originally posted by ray1993
one problem....

it is impossible to do that
Oh really?


There are 92 different solutions for an 8x8 board with 8 queens, 12 of these are unique solutions and the remaining 80 can be found from these 12 by rotations and translations.

Here is a method for finding a solution for a nxn board with n queens (n=1 or n>3):
1. Divide n by 12. Remember the remainder (it's 8 for the eight queens puzzle).
2. Write a list of the even numbers from 2 to n in order.
3. If the remainder is 3 or 9, move 2 to the end of the list.
4. Write the odd numbers from 1 to n in order, but, if the remainder is 8, switch pairs (i.e. 3, 1, 7, 5, 11, 9, &hellip๐Ÿ˜‰.
5. If the remainder is 2, switch the places of 1 and 3, then move 5 to the end of the list.
6. If the remainder is 3 or 9, move 1 and 3 to the end of the list.
7. Place the first-column queen in the row with the first number in the list, place the second-column queen in the row with the second number in the list, etc.

A slightly more challenging problem is to place 9 queens and a pawn on a chessboard such that no queen attacks any other queen. What about placing 10 queens and 2 pawns?

Z

Joined
20 Oct 05
Moves
611
12 Apr 06

Z

Joined
20 Oct 05
Moves
611
12 Apr 06

A

The Great North

Joined
26 Nov 05
Moves
1278
12 Apr 06

Originally posted by XanthosNZ
Oh really?
[fen]3Q4/6Q1/2Q5/7Q/1Q6/4Q3/Q7/5Q2 w - - 0 1[/fen]

There are 92 different solutions for an 8x8 board with 8 queens, 12 of these are unique solutions and the remaining 80 can be found from these 12 by rotations and translations.

Here is a method for finding a solution for a nxn board with n queens (n=1 or n>3):
1. Divide n by 12. Remem ...[text shortened]... hessboard such that no queen attacks any other queen. What about placing 10 queens and 2 pawns?
hey sure showed you're ass, ray

J

Joined
07 Apr 06
Moves
60
12 Apr 06

Yes really imposible to do that