Originally posted by ilywrin
[b]BigDoggProblem you're correct. The mate I had in mind was 1.d3 Nf6 2.Kd2 e6 3. Kc3 Qe7 4.Kd4 Qc5, so there is obviously more than one solution. As for the 4.Kb4 variation, there can be no mate in four moves .
Okay, I'm reposting the solution to the original problem:
1.f3 e6 (or e5)2.Kf2 Qf6 3. Kg3 Qf3 4. Kh4 Be7 #
Now after that loss, w ...[text shortened]... Ke3 4.Ke4 [/b], a plan the devious Black refuted with another mate on the fourth move. How?

[/b]

Originally posted by BLReid
1 d4 e6
2 Kd2 Qh4
3 Ke3 Qg3+
4 Ke4 Nf6#

Well yes, and also: 1...c6 2... Qc73...Qg34...d5#
Ah, well ...
Try a problem by S.Loyd (one of my favorite chess problems composers) White: Kc5, Qh1, Ne3, Bf3, pawns: f4, g2; Black: Kf2, pawns c6, f5. White to mate in 3. That is one hell of a puzzle 😉

let me try this new FEN feature:


S.Loyd
White to move and mate in 3