If black mirrors all of white's moves, then white to play and mate in four.

Hm. Not very hard. I thnk. My original idea is;
1. e4 e5
2. Bc4 Bc5
3. Qh5 Qh4
4. Qxf7#

I had 1. d4 2. Qd3 3. Qf5 4. Qxc8#

Originally posted by ares3
Hm. Not very hard. I thnk. My original idea is;
1. e4 e5
2. Bc4 Bc5
3. Qh5 Qh4
4. Qxf7#

Oh yeah. Told you that I only glanced. Thanks GP.
I'll check it harder.

is it from the starting position? i cant find any mate in 4 then.

Originally posted by crazyblue
is it from the starting position? i cant find any mate in 4 then.

Yep, zzyw has one solution. Congratulations. There are also two more possibilities.

nice, double blindness from me. neither did i see that posting, nor the solution. i just thought, it probably has to start with d-pawn (or another pawn) cause i couldnt find anything for e-pawn. good puzzle! 🙂

Originally posted by doodinthemood
Yep, zzyw has one solution. Congratulations. There are also two more possibilities.

not sure if this counts as a "different" solution to the one above, but 1.d4 2.Qd3 3.Qh3 4.Qxc8# works... same idea as 3.Qf5 though

Yep Aethereal, I'm assuming that they have to be radically different...🙁

well that is one, so there's one more solution left. It's just that Aethareal won himself no friends by posting it 😉

1. c4 c5 2. Qa4 Qa5 3. Qc6 Qc3 4. Qxc8#.

This was somewhat easy due to the fact that 4. Qxc8# has to be the 4th move.

I always assumed that in order for there to be three, they might be different. It'd be more fun that way, at least.