Originally posted by agrysonNo. That is simple. Here is one for you:
In line with our back away slowly policy, here's a chess like one...
An 8x8 board with alternating black and white squares (a chess board) has two diagonally opposite corners removed.
You are given a set of rectangular dominos, each one can cover exactly two squares.
Is it possible to cover every remaining square on the board without stacking or going over the edge of the board.
Person A says "you are dumb"
Person B says "Person A is lying"
Person C says "Person B is either telling the truth or lying"
Which one is telling the truth?
Person A says "you are dumb"
Person B says "Person A is lying"
Person C says "Person B is either telling the truth or lying"
Which one is telling the truth?
None of them, since "you are dumb" is not a matter of fact, but opinion. But if it were a matter of fact, then C would be telling the truth; B and A would be nondeterminable, except that one is telling the truth and the other is lying.
1: Add a match diagonally beteen the first two, another one diagonally between the fourth and fifth, and another three attached horizontally to the sixth one: |\| | |\| E
2: X|| - draw the line of symmetry to cut it in half, and you get V||
Now use exactly six matches to make four congruent equilateral triangles whose side length is the length of a match.
Originally posted by Jirakonits a tetrahedron.
1: Add a match diagonally beteen the first two, another one diagonally between the fourth and fifth, and another three attached horizontally to the sixth one: |\| | |\| E
2: X|| - draw the line of symmetry to cut it in half, and you get V||
Now use exactly six matches to make four congruent equilateral triangles whose side length is the length of a match.
three for the base and three standing erect at 60 degrees each.
GOtcha on that one.