24 Mar '07 00:46>
go to www.primarygames.com, open the math section and go to the tower of hanoi. Make a set of rules to solve. also figure out the least number of moves possible with a tower of 25 rings.
Originally posted by joe shmoBecause the two ways you mention are saying exactly the same:
There are two ways of achieving the answer, one way is to double the previous perfect moves and add one two get the next. The other, using the number of rings as the power of two and subtracting one. I can't see how these are related. can you help?
Originally posted by joe shmoWhen I did it the long way
do you think you can put that into words, if it's not to much trouble?
I have not yet solved an equation like that in my College Algebra 1 class
Is that a quadratic equation?
If not what level of math can I expect to see this.
Originally posted by joe shmoI am not up-to-date on math curricula. I expect this to be covered somewhere in 13 - 15 year age math. Let's try to make it simple:
do you think you can put that into words, if it's not to much trouble?
I have not yet solved an equation like that in my College Algebra 1 class
Is that a quadratic equation?
If not what level of math can I expect to see this.
Originally posted by Mephisto2thanks
I am not up-to-date on math curricula. I expect this to be covered somewhere in 13 - 15 year age math. Let's try to make it simple:
You have three spots s1, s2 and s3. To move the pile from s1 to s3 it works this way:
- a pile of 1 goes immedeately to s3 = 1 move
- a pile of 2 requires that you put first the top on s2, then the bottom on s3 folllowed ...[text shortened]... exactly what the formula +1 + 2^(n-1) means. And that formula is exactly the same as -1 + 2^n.
Originally posted by geepamoogleI think I'm halfway there, how would 4 pegs affect the series? I tinkered with it but had no sucess.
Let us call f(x) the number of moves required to move x discs in the Tower of Hanoi problem.
[b]f(1) = 1
f(x+1) = 2*f(x) +1
The first is easy to see, the second is you shift the previous x discs, move the one you want, then shift the prvious on top of it.
The simplest way to figure this out is to look at the series..
[i]1, 2*1+1=3, 2*3+ ...[text shortened]... ^(x-1) from 1 to x[/b], but this gets into summation notation, which is fairly advanced algebra.[/b]