First, let's assume that on earth, I can jump ~ 2ft, or 0.6m high.
Using equations for conservation of energy, we can determine my jumping velocity (really my landing velocity):
m*g*h = 0.5*m*v^2
or
v^2 = 2gh
Since g on earth is 9.8m/s^2, and my jump height is 0.6m
v^2 = 11.77 (m/s)^2
v = 3.43 m/s
Using the same equation in reverse to get my jump high on Ceres
11.77 = 2 * 0.27 * h
h = 21.8m
Originally posted by forkedknightWhat about the best humans can do? I think the present record is a bit over 8 feet! 2.44 meters! Would it be linear, since that would be 4 times higher, so Would that come out to 87.2 meters on Ceres?
First, let's assume that on earth, I can jump ~ 2ft, or 0.6m high.
Using equations for conservation of energy, we can determine my jumping velocity (really my landing velocity):
m*g*h = 0.5*m*v^2
or
v^2 = 2gh
Since g on earth is 9.8m/s^2, and my jump height is 0.6m
v^2 = 11.77 (m/s)^2
v = 3.43 m/s
Using the same equation in reverse to get my jump high on Ceres
11.77 = 2 * 0.27 * h
h = 21.8m
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Originally posted by sonhouseTo answer your question...yes the relation ship is linear. However, as it is, the equation is only good for vertical leap. That limits it it to standing still, and jumping without changing your body's center of mass with respect to the extended body. I don't think anyone has a true vertical leap of 8 ft here on earth.
What about the best humans can do? I think the present record is a bit over 8 feet! 2.44 meters! Would it be linear, since that would be 4 times higher, so Would that come out to 87.2 meters on Ceres?
If we consider that we could be assisted with our jump we can get even higher. The escape velocity on Ceres is reportedly 510 m/s. If we decide to not exceed 500 m/s to avoid an error in the escape velocity number then we get a height of:
500 / (2 * 0.27) = 926 m (rounded)
That same apparatus on earth would only get us 25.5 m [5 giraffes - see below], which is an impressive jump but gives you the idea of the escape velocity. Most people with a reasonably good arm can throw a ball this high, so we could stand on Ceres and 'throw' ball-massed satellites into orbit. That would save on gas! (https://what-if.xkcd.com/44/)
Originally posted by divegeesterOf course that is always true, but the momentum imparted to Ceres would be very small. Ceres has a mass of approximately 895.8E18 kg, whilst an average human has a mass of 80.7 kg. That is a HUGE difference and Ceres would move an very insignificant amount.
Would it be part jump and part push as Ceres would move away from us.
Originally posted by GastelEtswaneJob listing for the year 2145: Ceres needs people with good throwing arm to launch small payloads from surface, baseball pitchers may apply. Good working conditions, sign on bonus, one month vacation per year, very high salary...
If we consider that we could be assisted with our jump we can get even higher. The escape velocity on Ceres is reportedly 510 m/s. If we decide to not exceed 500 m/s to avoid an error in the escape velocity number then we get a height of:
500 / (2 * 0.27) = 926 m (rounded)
That same apparatus on earth would only get us 25.5 m [5 giraffes - see ...[text shortened]... row' ball-massed satellites into orbit. That would save on gas! (https://what-if.xkcd.com/44/)
Originally posted by sonhouseOnly Ceres-ious applicants should apply?
Job listing for the year 2145: Ceres needs people with good throwing arm to launch small payloads from surface, baseball pitchers may apply. Good working conditions, sign on bonus, one month vacation per year, very high salary...